问题描述
给定一个排序链表,删除所有重复的元素,使得每个元素只出现一次。
示例 1:
输入: 1->1->2 输出: 1->2
示例 2:
输入: 1->1->2->3->3 输出: 1->2->3
简单的一批,直接代码
默认节点类
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public ListNode deleteDuplicates(ListNode head) {
if (head == null || head.next == null) {
return head;
}
ListNode pre = head;
ListNode next = head.next;
while (next.next != null) {
if (next.val == pre.val) {
next = next.next;
pre.next = next;
}else {
pre = next;
next = next.next;
}
}
if (next.val == pre.val){
pre.next = null;
}
return head;
}
下边是大神写的
public ListNode deleteDuplicates(ListNode head) {
ListNode current = head;
while (current != null && current.next != null) {
if (current.next.val == current.val) {
current.next = current.next.next;
} else {
current = current.next;
}
}
return head;
}