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写在最前面:
为什么我觉得这道简单的题好难啊...感觉自己是个数学渣渣
纯原创,不会有人和我一样奇葩的思路的...
leetcode【400】Nth Digit
Find the nth digit of the infinite integer sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...
Note:
n is positive and will fit within the range of a 32-bit signed integer (n < 231).
Example 1:
Input:
3
Output:
3
Example 2:
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Input:
11
Output:
0
Explanation:
The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10.
求出几位数
在这个几位数的第几个
属于哪个数字
属于哪一个数字的第几个字符
自己领悟吧~
class Solution:
def findNthDigit(self, n):
"""
:type n: int
:rtype: int
"""
digit = 1
while n > digit*9*10**(digit-1):
n -= digit*9*10**(digit-1)
digit += 1
a = n // digit
b = n % digit
if a == 0:
c = 10 ** (digit-1) + a
else:
c = 10 ** (digit-1) + a -1
if b == 0:
return int(str(c)[digit-1])
else:
return int((str(c+1)[b-1]))