BZOJ 3790: 神奇项链

版权声明:本文为一名蒟蒻的原创文章,大神转载的话顺便说个出处呗。 https://blog.csdn.net/cgh_Andy/article/details/78878285

manacher一下,然后就变成经典的线段覆盖了(我打了贪心的那种)

#include<bits/stdc++.h>
using namespace std;
const int N=1e5+3,mod=1e9+7;
struct P{int l,r;}a[N];
bool Cmp(P x,P y){
    return x.l==y.l?x.r>y.r:x.l<y.l;
}
char s[N],c[N]; int n,r[N];
void manacher(){
    int mx=0,id;
    for(int i=1;i<=n;++i){
        if(mx>i)r[i]=min(r[id*2-i],mx-i); else r[i]=1;
        while(i+r[i]<=n && s[i-r[i]]==s[i+r[i]])++r[i];
        --r[i]; if(i+r[i]>mx)mx=i+r[i],id=i;
    }
}
int main(){
    while(~scanf("%s",c+1)){
        n=strlen(c+1); int m=0,i,ans=0;
        for(i=1;i<=n;++i)s[++m]='#',s[++m]=c[i];
        s[++m]='#',n=m;
        manacher();
        for(i=1;i<=n;++i)a[i]=(P){i-r[i],i+r[i]};
        sort(a+1,a+1+n,Cmp); i=1,m=0;
        while(1){
            int mx=0;
            for(;a[i].l<=m+1 && i<=n;++i)mx=max(mx,a[i].r);
            m=mx,++ans;
            if(m==n)break;
        }
        printf("%d\n",ans-1);
    }
    return 0;
}

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转载自blog.csdn.net/cgh_Andy/article/details/78878285