按两次返回键退出程序

在Activity中重写onKeyDown方法即可

private long mPreKeyBackTime = 0;
    private static final int EXIT_KEYBACK_DELTA_TIME = 2000;

    @Override
    public boolean onKeyDown(int keyCode, KeyEvent event) {
        if (keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN) {
            if ((System.currentTimeMillis() - mPreKeyBackTime) > EXIT_KEYBACK_DELTA_TIME) {
                Toast.makeText(getApplicationContext(), "再按一次退出程序", Toast.LENGTH_SHORT).show();
                mPreKeyBackTime = System.currentTimeMillis();
            } else {
                finish();
                System.exit(0);
            }
            return true;
        }
        return super.onKeyDown(keyCode, event);
    }

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转载自dandy-deng.iteye.com/blog/2222217