Oracle 日历

此方法只是用于Oracle数据库。

直接看例子吧：

select ceil((cdate+(to_char(to_date('20100101','yyyymmdd'),'d'))-2)/7) as week,


sum(decode(to_char(everyday,'d'),'2',to_char(everyday,'dd'))) as 星期一,

sum(decode(to_char(everyday,'d'),'3',to_char(everyday,'dd'))) as 星期二,

sum(decode(to_char(everyday,'d'),'4',to_char(everyday,'dd'))) as 星期三,

sum(decode(to_char(everyday,'d'),'5',to_char(everyday,'dd'))) as 星期四,

sum(decode(to_char(everyday,'d'),'6',to_char(everyday,'dd'))) as 星期五,

sum(decode(to_char(everyday,'d'),'7',to_char(everyday,'dd'))) as 星期六,

sum(decode(to_char(everyday,'d'),'1',to_char(everyday,'dd'))) as 星期日

from(

select everyday,everyday-TO_DATE('20100101','YYYYMMDD')+1 as cdate,decode(to_char(everyday,'d'),1,7,to_char(everyday,'d')-1) as sweek

from(

SELECT NEXT_DAY(TO_DATE('20100101','YYYYMMDD'),2)-7+LEVEL-1 AS everyday FROM DUAL CONNECT BY LEVEL <=(TRUNC(NEXT_DAY(LAST_DAY(TO_DATE('20100101','YYYYMMDD')),2))-(TRUNC(NEXT_DAY(TO_DATE('20100101','YYYYMMDD'),2))-7))

    )

)group by ceil((cdate+(to_char(to_date('20100101','yyyymmdd'),'d'))-2)/7) order by 1

结果---------------------------------------------------------------------------------------------------------------------------

如果不需要本月前后的日期，即上个月的 28，29，30，31号

只需修改以上代码就可以，当然也可以更简单，如下

select ceil((to_char(everyday,'dd')+(to_char(to_date('20100101','yyyymmdd'),'d'))-2)/7) as week,


sum(decode(to_char(everyday,'d'),'2',to_char(everyday,'dd'))) as 星期一,

sum(decode(to_char(everyday,'d'),'3',to_char(everyday,'dd'))) as 星期二,

sum(decode(to_char(everyday,'d'),'4',to_char(everyday,'dd'))) as 星期三,

sum(decode(to_char(everyday,'d'),'5',to_char(everyday,'dd'))) as 星期四,

sum(decode(to_char(everyday,'d'),'6',to_char(everyday,'dd'))) as 星期五,

sum(decode(to_char(everyday,'d'),'7',to_char(everyday,'dd'))) as 星期六,

sum(decode(to_char(everyday,'d'),'1',to_char(everyday,'dd'))) as 星期日

from(select everyDay,decode(to_char(everyDay,'d'),1,7,to_char(everyDay,'d')-1) as sweek from( select to_date('20100101','yyyymmdd') + level - 1 as everyDay

from dual connect by level <= (last_day(to_date('20100101','yyyymmdd')) - to_date('20100101','yyyymmdd') +1))

)

group by ceil((to_char(everyday,'dd')+(to_char(to_date('20100101','yyyymmdd'),'d'))-2)/7) order by 1;

结果下：-----------------------------------------------------------------------------------------------------------------------

PS：年历的实现方式

只需要修改红色部分代码中的日期既可以实现，我在这里不贴出效果图了，当然oracle也提供了年历的代码，

不过是以周日作为一周的第一天，oracle代码如下：

select case


when (new_yweek = min(new_yweek)over(partition by mon order by new_yweek)) then

mon_name

else

null

end as month,

new_yweek as yweek,

row_number() over(partition by mon order by new_yweek) as mweek,

sum(decode(wday, '1', mday, null)) as sun,

sum(decode(wday, '2', mday, null)) as mon,

sum(decode(wday, '3', mday, null)) as tue,

sum(decode(wday, '4', mday, null)) as wed,

sum(decode(wday, '5', mday, null)) as thu,

sum(decode(wday, '6', mday, null)) as fri,

sum(decode(wday, '7', mday, null)) as sat

from (select dayofyear as everyday,

to_char(dayofyear, 'mm') as mon,

to_char(dayofyear, 'Month') as mon_name,

to_char(dayofyear, 'w') as mweek,

to_char(dayofyear, 'ww') as yweek,

case

when (to_char(to_date(:year || '0101', 'yyyymmdd'), 'd') > '1') and

(to_char(dayofyear, 'd') <

to_char(to_date(:year || '0101', 'yyyymmdd'), 'd')) then

to_char(to_char(dayofyear, 'ww') + 1, 'fm00')

else

to_char(dayofyear, 'ww')

end as new_yweek,

to_char(dayofyear, 'd') as wday,

to_char(dayofyear, 'dd') as mday

from (select to_date(:year || '0101', 'yyyymmdd') + level - 1 as dayofyear

from dual

connect by level <= to_char(to_date(:year || '0131', 'yyyymmdd'),'ddd')

)

)


group by mon, mon_name, new_yweek

只要稍微变换一下，就可以实现很多种需求，有兴趣的朋友可以自己试一下。

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