题目链接:https://pintia.cn/problem-sets/994805342720868352/problems/994805367156883456
思路:(1)整行输入,分别对数字和字符串处理
(2)对字符串要判断是一串还是两串,然后判断是十位还是个位
(3)对数字判断十位和个位存在与否,注意:这里第一次出错了,因为整13是tam,不是tam tret。
#include<iostream>
#include<cstring>
#include<cstdio>
#include<string>
using namespace std;
string b1[20]={"tret","jan","feb","mar","apr","may",
"jun","jly","aug","sep","oct","nov","dec"};
string b2[20]={"","tam","hel","maa","huh","tou","kes",
"hei","elo","syy","lok","mer","jou"};
int main(void)
{
int n,i,ans,j;
cin>>n;
getchar();
string s1;
for(i=0;i<n;i++)
{
getline(cin,s1);
if(s1[0]>='0'&&s1[0]<='9')
{
ans=0;
for(j=0;j<s1.length();j++)
ans=ans*10+s1[j]-'0';
int t1=ans/13,t2=ans%13;
if(t1==0)
cout<<b1[t2]<<endl;
else
{
if(t2) cout<<b2[t1]<<" "<<b1[t2]<<endl;
else cout<<b2[t1]<<endl;
}
}
else
{
string s2="",s3="";
int fg=0;
for(j=0;j<s1.length();j++)
if(s1[j]==' ')
{
fg=1;break;
}
if(fg==0)
{
int pt=0;
for(j=0;j<13;j++)
if(s1==b1[j])
{
cout<<j<<endl;pt=1;break;
}
if(pt==0)
{
for(j=1;j<13;j++)
if(s1==b2[j])
{
cout<<j*13<<endl;break;
}
}
}
else
{
ans=0;
for(j=0;j<s1.length()&&s1[j]!=' ';j++) s2+=s1[j];
for(j++;j<s1.length();j++) s3+=s1[j];
for(j=1;j<13;j++)
if(s2==b2[j])
{
ans+=j*13;break;
}
for(j=0;j<13;j++)
if(s3==b1[j])
{
ans+=j;break;
}
cout<<ans<<endl;
}
}
}
return 0;
}