华为OJ--合法IP的判断

练习时,查询到CSDN有为博主提供了IP的判断算法,如连接http://blog.csdn.net/dzyhenry/article/details/8138322

提交后,未通过验证,几经改进,通过了测试,但只拿到及格分数60.

代码如下:请各位指点一二


int IsValueValid(char IP[]) 


{ 


      char *p = IP;


      if(p[0] <'0' ||p[0] >'9')


             return 0;  


      int Len,Integer, DotCnt;


      Len=Integer=DotCnt=0; 


      char LastChar;


   while(*p !='\0') 


   { 


       if((*p)>='0' &&(*p) <='9')  


             {


                    Integer= Integer*10 + *p - '0';


                    Len++;


                    if(Len >3)


                           return 0;


             } 


             else if(*p !='.' ||Integer > 255 ||((*p == '.')&& LastChar == '.' ))


                    return 0;


             else


             {


                            DotCnt++;


                           Integer= 0; 


                           Len= 0;              


             }


             LastChar= *p;


       p++; 


   } 


       if(DotCnt ==3) 


       return1;  


   else   


      return0; 


} 


 


int main() 


{ 


      char IpAddress[18]; 


      cout << "Please input the ip address: \n";


      cin >> IpAddress; 


      if(IsValueValid(IpAddress)) 


             cout<<"YES";     


      else 


              cout << "NO";


  return0; 

} 



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转载自blog.csdn.net/zhang_fei_fresh/article/details/49367195