Given an array consisting of n
integers, find the contiguous subarray of given length k
that has the maximum average value. And you need to output the maximum average value.
Example 1:
Input: [1,12,-5,-6,50,3], k = 4
Output: 12.75
Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75
Note:
- 1 <=
k
<=n
<= 30,000. - Elements of the given array will be in the range [-10,000, 10,000].
题解:
class Solution {
public:
double findMaxAverage(vector<int>& nums, int k) {
int n = nums.size();
double maxi = INT_MIN;
for (int i = 0; i <= n - k; i++) {
double sum = 0;
for (int j = i; j < i + k; j++) {
sum += nums[j];
}
double avg = sum / k;
if (avg > maxi) {
maxi = avg;
}
}
return maxi;
}
};