Find The Multiple
Time Limit: 1000MS | Memory Limit: 10000K | |||
Total Submissions: 43948 | Accepted: 18417 | Special Judge |
Description
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
Source
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int n;
int flag;
int dfs(unsigned long long s,int step)
{
if(flag==1||step==19)
return 0;
else if(s%n==0)
{
printf("%I64u\n",s);
flag=1;
return 1;
}
else
{
if(!dfs(s*10,step+1))
dfs(s*10+1,step+1);
}
}
int main()
{
while(~scanf("%d",&n)&&n)
{flag=0;
dfs(1,0);
}
return 0;
}