#include<stdio.h>
int main()
{int njc(int n);
int x,n,y;
scanf("%d",&n);
y=njc(n);
printf("%d",y);
return 0;
}
int njc(int n)
{
int z;
if(n==0||n==1)
return 1;
else z=njc(n-1)*n;
return (z);
}
C语言 用递归法求n的阶乘
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转载自blog.csdn.net/weixin_43742177/article/details/84711644
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