func getStepNumber(n:Int) -> Int {
if 0 > n{
return 0;
}
if n == 1 {
return 1;
}
if n == 2 {
return 2;
}
if n > 2 {
return getStepNumber(n: n - 1) + getStepNumber(n: n - 2);
}
return 0;
}
let num = getStepNumber(n: 9)
print(num)
Swift实现n节阶梯
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转载自blog.csdn.net/qq_43361450/article/details/84727688
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