#求解非线性方程组2x1-x2^2=1,x1^2-x2=2 from scipy.optimize import fsolve #导入求解方程组的函数 from scipy import integrate def func(x:list): x1=x[0] x2=x[1] xy=[2*x1-x2**2-1,x1**2-x2-2] result=fsolve(xy,x) #输入初始值,并求解 return result def g(y): return (1-y**2)**0.5 pi_2,err=integrate.quad(g,-1,1) #积分结果和误差 print(pi_2*2)
python Scipy求解非线性方程组和数值积分
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