给定某年某月某日,将其转换成这一年的第几天并输出。
提示:a[2][13]={{0,31,29,31,30,31,30,31,31,30,31,30,31},{0,31,28,31,30,31,30,31,31,30,31,30,31}};
#include<stdio.h>
int main()
{
int a[2][13] ={
{ 0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 },
{ 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }
};
int i, j, year, month, day=0;
printf("请输入年月日\n");
scanf("%d%d%d", &year, &month, &day);
if ((year % 4) == 0 && (year % 100) != 0 || (year % 400) == 0)
for (i = 1; i < month; i++)
day = day + a[0][i];
else
for (i = 1; i < month; i++)
day = day + a[1][i];
printf("这一年的第%d天\n", day);
return 0;
}