test5_1201

1.完成猜数字游戏。

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>

//.完成猜数字游戏
void Menu() {
	printf("----------------------------\n");
	printf("---------1.开始游戏---------\n");
	printf("---------2.游戏结束---------\n");
	printf("----------------------------\n");
}
void Game() {
	int rand_num = rand() % 100 + 1;
	int input = 0;

	while (1) {
		printf("请输入一个数(1-100): ");
		scanf("%d", &input);

		if (input > rand_num) {
			printf("高了!\n");
		}
		else if (input < rand_num) {
			printf("低了!\n");
		}
		else {
			printf("你猜对了!\n");
			break;
		}
	}
}
int main() {
	while (1) {
		Menu();

		int input = 0;
		srand(time(0));
		printf("请选择(1or2):");
		scanf("%d", &input);

		if (input == 1) {
			Game();
		}
		else if (input == 2) {
			printf("游戏将在三秒后结束!\n");
			Sleep(3000);
			exit(0);
		}
		else {
			printf("输入错误 \n");
		}
	}

	system("pause");
	return 0;
}



2.写代码可以在整型有序数组中查找想要的数字,
找到了返回下标,找不到返回-1.(折半查找)

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <String.h>
#include <windows.h>

int main() {
	int arr[10] = { 1,2,3,4,5,6,7,8,9,10 };
	int left = 0;
	int right = sizeof(arr) / sizeof(arr[0]) - 1;
	int mid = 0;
	int key = 0;
	printf("输入要查找的数:");
	scanf("%d", &key);

	while (left <= right) {
		mid = (left + right) / 2;
		if (arr[mid]< key){
			left = mid + 1;
		}
		else if (arr[mid] > key) {
			right = mid - 1;
		}
		else {
			break;
		}
	}
	if (left <= right) {
		printf("找到了!%d\n", mid);
	}
	else {
		printf("没找到!\n");
	}

	system("pause");
	return 0;
}
int half_search(int key) {
	int arr[10] = { 1,2,3,4,5,6,7,8,9,10 };
	int left = 0;
	int right = sizeof(arr) / sizeof(arr[0]) - 1;
	printf("请输入你要查找的数:");
	scanf("%d", &key);

	while (left <= right) {

		int mid = (left + right) / 2;
		if (arr[mid] < key) {
			//往右找
			left = mid + 1;
		}
		else if (arr[mid] > key) {
			//往左找
			right = mid - 1;
		}
		else {
			return mid;
		}
	}
	return -1;
}

int main() {
	int arr[10] = { 0 };
	int key = 0;
	int result = half_search(arr[10], key);
	printf("%d\n", result);

	system("pause");
	return 0;
}



3.编写代码模拟三次密码输入的场景。
最多能输入三次密码,密码正确,提示“登录成功”,密码错误,
可以重新输入,最多输入三次。三次均错,则提示退出程序。

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <String.h>
#include <windows.h>

int main() {
	int n = 0;

	for (n = 1; n <= 3; n++) {
		char arr[10] = "";
		printf("请输入密码:");
		scanf("%s", arr);

		if (strcmp(arr, "abcde") == 0) {
			printf("登录成功!\n");
			break;
		}
		else {
			printf("登录失败!\n");
			printf("请重新输入(您还可继续输入%d次)\n", (3 - n));
		}
	}
	if (n > 3) {
		printf("输入超过三次m程序结束!\n");
		Sleep(5000);
		exit(1);
	}

	system("pause");
	return 0;
}


4.编写一个程序,可以一直接收键盘字符,
如果是小写字符就输出对应的大写字符,
如果接收的是大写字符,就输出对应的小写字符,
如果是数字不输出。
 

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <String.h>
#include <windows.h>

int main() {
	int ch = 0;
	printf("请输入一个字符:\n");
	while ((ch = getchar()) != EOF) {
		if (ch >= 'a' && ch <= 'z'){
			printf("%c对应%c\n", ch, (ch-32));
		}
		else if (ch >= 'A' && ch <= 'Z') {
			printf("%c对应%c\n", ch, (ch+32));
		}
		else if (ch >= '0' && ch <= '9') {
			printf("不能输入数字,程序将在1s后退出");
			Sleep(1000);
			exit(0);
		}
	}

	system("pause");
	return 0;
}

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转载自blog.csdn.net/Q_feifeiyu/article/details/84799824