1、依次输入五句话,然后将它逆序输出
Scanner input = new Scanner ( System. in) ;
String[ ] s = new String [ 5 ] ;
System. out. println ( "请输入5句话" ) ;
for ( int i= 0 ; i< s. length; i++ ) {
System. out. print ( "第" + ( i+ 1 ) + "句话:" ) ;
s[ i] = input. nextLine ( ) ;
}
System. out. println ( "\n逆序输出5句话为:" ) ;
for ( int i= s. length- 1 ; i>= 0 ; i-- ) {
System. out. println ( s[ i] ) ;
}
input. close ( ) ;
2、某百货商场当日消费积分最高的八名顾客,他们的积分分别是:18、25、7、36、13、2、89、63.编写程序找出最低的积分及它在数组中的原始位置[下标]
int [ ] points = { 18 , 25 , 7 , 36 , 13 , 2 , 89 , 63 } ;
int min = points[ 0 ] , index = 0 ;
for ( int i= 1 ; i< points. length; i++ ) {
if ( min> points[ i] ) {
min = points[ i] ;
index = i;
}
}
System. out. println ( "最低的积分为:" + min+ ",其在数组中的原始位置为:" + index) ;
3、从键盘输入10个整数,合法值为1、2或3,不是这三个数则为非法数字。试编程统计每个整数和非法数字的个数
Scanner input = new Scanner ( System. in) ;
int [ ] a = new int [ 10 ] ;
int [ ] tj = new int [ 4 ] ;
System. out. println ( "请输入10个数" ) ;
for ( int i= 0 ; i< 10 ; i++ ) {
a[ i] = input. nextInt ( ) ;
switch ( a[ i] ) {
case 1 :
tj[ 1 ] ++ ;
break ;
case 2 :
tj[ 2 ] ++ ;
break ;
case 3 :
tj[ 3 ] ++ ;
break ;
default :
tj[ 0 ] ++ ;
break ;
}
}
System. out. print ( "输入的10个数为:" ) ;
for ( int i= 0 ; i< 10 ; i++ ) {
System. out. print ( a[ i] + " " ) ;
}
System. out. println ( ) ;
for ( int i= 1 ; i< tj. length; i++ ) {
System. out. println ( "数字" + i+ "的个数:" + tj[ i] ) ;
}
System. out. println ( "非法数字的个数:" + tj[ 0 ] ) ;
input. close ( ) ;
4、假设有一个长度为5的数组,如下所示。
int[] array = new int[]{1,3,-1,5,-2};
现要创建一个新数组 newArray[],要求新数组中的元素与原数组中的元素逆序,并且如果原数组中的元素值小于0,在新数组中按0存储。试编程输出新数组中的元素
int [ ] array = new int [ ] { 1 , 3 , - 1 , 5 , - 2 } ;
int [ ] newArray = new int [ array. length] ;
for ( int i= 0 , j= array. length- 1 ; i< array. length; i++ , j-- ) {
newArray[ i] = array[ j] ;
if ( newArray[ i] < 0 ) {
newArray[ i] = 0 ;
}
}
System. out. println ( "原数组为:" ) ;
for ( int i = 0 ; i< array. length; i++ ) {
System. out. print ( array[ i] + " " ) ;
}
System. out. println ( "\n逆序并处理后的数组为:" ) ;
for ( int i = 0 ; i< newArray. length; i++ ) {
System. out. print ( newArray[ i] + " " ) ;
}