#include <stdio.h>
#include <stdlib.h>
void main()
{
int i, n;
double num = 0.0, sum = 0.0;
for (i = 1; i <= 100;i++ )
{ if (i%2==0)
n = -1;
else
n = 1;
num = n*1.0 / i;
sum = sum + num;
}
printf("结果为%f\n", sum);
system("pause");
}
计算1/1-1/2+1/3-1/4+1/5······+1/99-1/100的值
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转载自blog.csdn.net/qq_43765564/article/details/84726781
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