# 元祖 只读列表,可循环查询,可切片。
# 儿子不能改,孙子可能可以改。
# tu = (1,2,3,'alex',[2,3,4,'taibai'],'egon')
# # print(tu[3])
# # print(tu[0:4])
# # for i in tu:
# # print(i)
# tu[4][3]=tu[4][3].upper()
# print(tu)
# tu[4].append('sb')
# print(tu)
# s = 'alex'
# s1 = 'sb'.join(s)
# print(s1)
# 列表转化成字符串 list -----> str join
# li = ['taibai','alex','wusir','egon','女神',]
# s = '++++'.join(li)
# str ----->list split()
# print(s)
# range [1,2,3,4,5,6,.......100........]
# for i in range(3,10):
# print(i)
# for i in range(10):
# print(i)
# for i in range(0,10,3):
# print(i)
# for i in range(10,0,-2):
# print(i)
# for i in range(10,-1,-2):
# print(i)
li = [1, 2, 3, 5, 'alex', [2, 3, 4, 5, 'taibai'], 'afds']
# for i in li:
# if type(i) == list:
# for k in i:
# print(k)
# else:print(i)
for i in range(len(li)):
if type(li[i]) == list:
for j in li[i]:
print(j)
else:
print(li[i])
元组的嵌套,range,for循环嵌套
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转载自blog.csdn.net/ycdxw_xx/article/details/81910483
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