1.创建测试表
-
CREATE TABLE `location` (
-
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
-
`name` varchar(50) NOT NULL,
-
`longitude` decimal(13,10) NOT NULL,
-
`latitude` decimal(13,10) NOT NULL,
-
PRIMARY KEY (`id`),
-
KEY `long_lat_index` (`longitude`,`latitude`)
-
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
2.插入测试数据
-
insert into location(name,longitude,latitude) values
-
('广州东站',113.332264,23.156206),
-
('林和西',113.330611,23.147234),
扫描二维码关注公众号,回复: 4474883 查看本文章 -
('天平架',113.328095,23.165376);
-
mysql> select * from `location`;
-
+----+--------------+----------------+---------------+
-
| id | name | longitude | latitude |
-
+----+--------------+----------------+---------------+
-
| 1 | 广州东站 | 113.3322640000 | 23.1562060000 |
-
| 2 | 林和西 | 113.3306110000 | 23.1472340000 |
-
| 3 | 天平架 | 113.3280950000 | 23.1653760000 |
-
+----+--------------+----------------+---------------+
3.搜寻1公里内的数据
搜寻点坐标:时代广场 113.323568, 23.146436
6370.996公里为地球的半径
计算球面两点坐标距离公式
-
C = sin(MLatA)sin(MLatB)cos(MLonA-MLonB) + cos(MLatA)cos(MLatB)
-
Distance = RArccos(C)*Pi180
根据计算公式得到查询语句如下:
-
select * from `location` where (
-
acos(
-
sin(([#latitude#]*3.1415)/180) * sin((latitude*3.1415)/180) +
-
cos(([#latitude#]*3.1415)/180) * cos((latitude*3.1415)/180) * cos(([#longitude#]*3.1415)/180 - (longitude*3.1415)/180)
-
)*6370.996
-
)<=1;
执行查询:
-
mysql> select * from `location` where (
-
-> acos(
-
-> sin((23.146436*3.1415)/180) * sin((latitude*3.1415)/180) +
-
-> cos((23.146436*3.1415)/180) * cos((latitude*3.1415)/180) * cos((113.323568*3.1415)/180 - (longitude*3.1415)/180)
-
-> )*6370.996
-
-> )<=1;
-
+----+-----------+----------------+---------------+
-
| id | name | longitude | latitude |
-
+----+-----------+----------------+---------------+
-
| 2 | 林和西 | 113.3306110000 | 23.1472340000 |
-
+----+-----------+----------------+---------------+