class Solution: def repeatedNTimes(self, A): doubleN = len(A) N = doubleN / 2 dic = {} for a in A: if a in dic.keys(): dic[a]=dic[a]+1 else: dic[a]=1 if dic[a]==N: return a
leetcode961
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转载自www.cnblogs.com/asenyang/p/10164663.html
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