CSU 1442: NASSA’s Robot 1446: Modified LCS 1447: Mario Kart 1453: 平衡序列

1442: NASSA’s Robot

#include <iostream>
using namespace std;

int main()
{
    int T;
    cin >> T;
    while(T--)
    {
        int x, y, n;
        x = y = n = 0;
        string s;
        cin >> s;
        for (int i = 0; i < s.size(); i++)
            switch(s[i])
            {
                case 'U': y += 1; break;
                case 'D': y -= 1; break;
                case 'L': x -= 1; break;
                case 'R': x += 1; break;
                case '?': n += 1; break;
            }
        printf("%d %d %d %d\n", x-n, y-n, x+n, y+n);
    }
    return 0;
}
/**********************************************************************
	Problem: 1442
	User: 3901140225
	Language: C++
	Result: AC
	Time:52 ms
	Memory:2340 kb
**********************************************************************/


1446: Modified LCS


#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <cmath>
typedef long long ll;
using namespace std;

ll x, y, g;

void exgcd(ll a, ll b) {
	if (b == 0) {
		x = 1;
		y = 0;
		g = a;
		return;
	}
	exgcd(b, a%b);
	ll t = x;
	x = y;
	y = t - a / b * y;
	return;
}

int main() {
	int t;
	ll n1, n2, f1, f2, d1, d2;
	scanf("%d", &t);
	while (t--) {
		cin >> n1 >> f1 >> d1 >> n2 >> f2 >> d2;
		ll f = f2 - f1;
		exgcd(d1, -d2);
		if (f % g) {
			printf("0\n");
			continue;
		}
		else {
			ll r = abs((-d2)/g);
			x = ((x * f / g) % r + r) % r;
			y = (f - x * d1) / (-d2);
			ll dx = abs(d1 / g);
			ll dy = abs(d2 / g);
			ll ans = min((n1 - 1 - x) / dy, (n2 - 1 - y) / dx) + 1;
			cout << ans << endl;
		}
	}
	return 0;
}
/**********************************************************************
	Problem: 1446
	User: 3901140225
	Language: C++
	Result: AC
	Time:4 ms
	Memory:2024 kb
**********************************************************************/


1447: Mario Kart

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <string>
#include <iomanip>
#include <queue>
#include <vector>
#include <set>
#include <map>
#define LL long long
#define inf 0x3f3f3f3f
#define P system("pause")
using namespace std;
#define M 105
int cost[105],val[105],n,m,L;
int p[105],g[M][M],dp[1005],dis[M],vis[M];
void DP()//背包
{
    for(int i=0;i<1005;i++)
        dp[i]=inf;
    dp[0]=0;
    for(int i=0;i<m;i++)
    {
        for(int j=p[n-1]-p[0];j>=val[i];j--)
            dp[j]=min(dp[j],dp[j-val[i]]+cost[i]);
    }
}
void build()//建图
{
    for(int i=0;i<n;i++)
        for(int j=0;j<n;j++)
            g[i][j]=(p[i]==p[j])?0:inf;
    for(int i=0;i<n;i++)
    {
        for(int j=i+1;j<n;j++)
        {
            if(dp[p[j]-p[i]]<=L){
                g[i][j]=g[j][i]=1;
                //cout<<p[i]<<"->"<<p[j]<<endl;
            }
        }
    }
}
int dij(int u)//dijskstra求最短路
{
    int i,j,v;
    memset(vis,0,sizeof(vis));
    for(i=0;i<n;i++)
        dis[i]=g[u][i];
    dis[u]=0;
    vis[u]=1;
    for(i=1;i<n;i++)
    {
        int mi=inf,v=u;
        for(j=0;j<n;j++)
        {
            if(!vis[j]&&dis[j]<mi){
                mi=dis[j];
                v=j;
            }
        }
        vis[v]=1;
        for(j=0;j<n;j++)
        {
            if(!vis[j]&&dis[j]>dis[v]+g[v][j])
                dis[j]=dis[v]+g[v][j];
        }
    }
    int ans=dis[n-1];
    if(ans==inf)
        return -1;
    return ans;
}
int main()
{
    int t,i;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d%d",&n,&m,&L);
        for(i=0;i<n;i++)
            scanf("%d",&p[i]);
        for(i=0;i<m;i++)
            scanf("%d%d",&cost[i],&val[i]);
        sort(p,p+n);
        DP();
        build();
        printf("%d\n",dij(0));
    }
    return 0;
}
/**********************************************************************
	Problem: 1447
	User: 3901140225
	Language: C++
	Result: AC
	Time:44 ms
	Memory:2072 kb
**********************************************************************/



1453: 平衡序列

#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
using namespace std;
#define inf (0x3f3f3f3f)
typedef long long int LL;

#include <iostream>
#include <sstream>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <string>
const int maxn = 100000+20;
struct data
{
    int L,R,mx; //每个节点,都记录一个区间[L,R]。还有记录区间总和
    int mid() {return (L + R)/2;}
}SegTree[maxn<<2];  //右移两位,就是*4

void built (int root,int begin,int end)
{
    SegTree[root].L = begin; SegTree[root].R = end;//覆盖区间
    if (begin == end)
    {
        SegTree[root].mx = 0;  return ;
    }
    built(root<<1,begin,SegTree[root].mid());
    built(root<<1|1,SegTree[root].mid()+1,end);
    SegTree[root].mx = max(SegTree[root<<1].mx,SegTree[root<<1|1].mx);
    return ;
}
void add (int root,int pos,int val)
{
    if (SegTree[root].L == pos && pos == SegTree[root].R)
    {
        SegTree[root].mx = val;     return ;
    }
    if (pos <= SegTree[root].mid())     add(root<<1,pos,val);
    else if (pos >= SegTree[root].mid()+1)     add(root<<1|1,pos,val);
    SegTree[root].mx = max (SegTree[root<<1].mx,SegTree[root<<1|1].mx);
    return ;
}
//[begin,end]是要查询的区间,如果所求区间包含线段树覆盖区间,就可以返回
int find (int root,int begin,int end) //区间查询
{
    //查询[1,7]的话,左子树区间覆盖了[1,6],也可以直接返回,左子树最大值嘛
    if (begin <= SegTree[root].L && end >= SegTree[root].R) return SegTree[root].mx; //覆盖了
    if (end <= SegTree[root].mid()) //完全在左子数
        return find(root<<1,begin,end);
    else if (begin >= SegTree[root].mid() + 1) //完全在右子树
        return find(root<<1|1,begin,end);
    else
    {
        int Lmax = find(root<<1,begin,end);
        int Rmax = find(root<<1|1,begin,end);
        return max(Lmax,Rmax);
    }
}

void work ()
{
    built(1,0,maxn-20);
    int n;
    int k;
    scanf ("%d%d",&n,&k);
    for (int i=1;i<=n;++i)
    {
        int x;
        scanf ("%d",&x);
        int a = max(0,x-k);
        int b = min(maxn-20,x+k);
        int t = find(1,a,b);
        add(1,x,t+1);
    }
    printf ("%d\n",find(1,0,maxn-20));
    return ;
}

int main()
{
#ifdef local
    freopen("data.txt","r",stdin);
#endif
    int t;
    scanf ("%d",&t);
    while(t--) work();
    return 0;
}
/**********************************************************************
	Problem: 1453
	User: 3901140225
	Language: C++
	Result: AC
	Time:1484 ms
	Memory:6712 kb
**********************************************************************/

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