替换特殊字符:将‘\'’替换为空格
def check_quoto(str, n):
for i in range(len(str) - int(n)):
npos_q = -1
npos_b = -1
while keys[i + int(n)].count('\'') > 0:
npos_q = str[i + int(n)].find('\'')
npos_b = str[i + int(n)].find(' ')
keys[i + int(n)] = replaceString(str[i + int(n)], npos_q, ' ')
if npos_q >= 0 or npos_b > 0:
keys[i + int(n)] = '\'' + keys[i + int(n)] + '\''
return keys
def replaceString(string, num, replace):
string2 = ''
for i in range(len(string)):
if i == num:
string2 += replace
else:
string2 += string[i]
return string2