LeetCode50. Pow(x, n)(C++)

Implement pow(xn), which calculates x raised to the power n (xn).

Example 1:

Input: 2.00000, 10
Output: 1024.00000

Example 2:

Input: 2.10000, 3
Output: 9.26100

Example 3:

Input: 2.00000, -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25

Note:

  • -100.0 < x < 100.0
  • n is a 32-bit signed integer, within the range [−231, 231 − 1]

注意n=-2147482648(-2^31)的情况

class Solution {
public:
    double myPow(double x, int n) {
        if(n==0)
           return 1;
        else if(n<0)
            return 1.0/myPow(x,-(n+1))*(1.0/x);
        double y=myPow(x,n/2);
        return y*y*(n%2==0 ? 1 : x);
    }
};

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转载自blog.csdn.net/qq_41562704/article/details/86505751