题目：

传送门

分析：

表示最小生成树很可做

代码：

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring> 
#include<cstdlib>
#include<algorithm>
#include<set>
#include<queue>
#include<vector>
#include<map>
#include<list>
#include<ctime>
#include<iomanip>
#include<string>
#include<bitset>
#include<deque>
#include<set>
#define LL long long
#define ch cheap
using namespace std;
inline LL read() {
    LL d=0,f=1;char s=getchar();
    while(s<'0'||s>'9'){if(s=='-')f=-1;s=getchar();}
    while(s>='0'&&s<='9'){d=d*10+s-'0';s=getchar();}
    return d*f;
}
struct node{
	int x,y,w;
}e[2000005];
int x[1000005],y[1000005];
int f[1000005];
int find(int i) {return f[i]==i?i:f[i]=find(f[i]);}
bool cmp(node x,node y) {return x.w<y.w;}
int main()
{
	freopen("pupil.in","r",stdin);
	freopen("pupil.out","w",stdout);
	int n=read(),a=read(),b=read();
	for(int i=1;i<=n;i++) x[i]=read(),y[i]=read();
	int m=0;
	for(int i=1;i<=n;i++)
	  for(int j=1;j<=n;j++)
		{
		  if(i==j) continue;
		  e[++m].x=i;e[m].y=j;
		  e[m].w=(abs(x[i]-x[j])+abs(y[i]-y[j]))*b;
		}
	for(int i=1;i<=n;i++)
	  e[++m].x=0,e[m].y=i,e[m].w=a;
	sort(e+1,e+1+m,cmp);
	for(int i=0;i<=n;i++) f[i]=i;
	int ans=0;
	for(int i=1;i<=m;i++)
	{
		if(find(e[i].x)==find(e[i].y)) continue;
		f[find(e[i].x)]=find(e[i].y);
		ans+=e[i].w;
	}
	cout<<ans;
	return 0;
}