A+B Problem
Problem Description
INPUT
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
OUTPUT
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
问题链接：https://vjudge.net/problem/HDU-2101
问题分析：因为要多组输入，所以先将结果保存在一个数组中，并用一个变量统计有多少个结果，后用循环输出并判断如果
为0则输出YES否则输出NO，但这种方法会超时，有待修改。
TEL代码如下：
#include <iostream>
using namespace std;
int main()
{
int s[100] = { 0 };
int a = 0, b = 0, i = 0, c = 0;
while (cin >> a >> b)
{
s[i] = (a + b) % 86;
i++;
}
for (int j = 0; j < i; j++)
{
cout << (s[j] == 0 ? "yes" : "no") << endl;
}
}