JSON多参数传输时处理

var one = "one";
var two = "two",
var three = "three"

var json = {
	"one": one,
	"two": two,
	"three":three
}

$.getJSON(url,json,function(data) {
	alert('返回值');
});

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转载自blog.csdn.net/qq_40820862/article/details/86318909