版权声明:知识内容为原创思考,转载请注明:转自 https://blog.csdn.net/SmartLoveyu/article/details/86663891
如题:
利用系统功能调用从键盘输入,转换后在屏幕上显示,具体要求如下:
(1) 如果输入的是字母(A~Z,区分大小写)或数字(0~9),则将其转换成对应的英文单词后在屏幕上显示,对应关系见下表
(2) 若输入的不是字母或数字,则在屏幕上输出字符“*”,
(3) 每输入一个字符,即时转换并在屏幕上显示,
(4) 支持反复输入,直到按“?”键结束程序。
A | Alpha | N | November | 1 | First | a | alpha | n | november |
B | Bravo | O | Oscar | 2 | Second | b | bravo | o | oscar |
C | China | P | Paper | 3 | Third | c | china | p | paper |
D | Delta | Q | Quebec | 4 | Fourth | d | delta | q | quebec |
E | Echo | R | Research | 5 | Fifth | e | echo | r | research |
F | Foxtrot | S | Sierra | 6 | Sixth | f | foxtrot | s | sierra |
G | Golf | T | Tango | 7 | Seventh | g | golf | t | tango |
H | Hotel | U | Uniform | 8 | Eighth | h | hotel | u | uniform |
I | India | V | Victor | 9 | Ninth | i | india | v | victor |
J | Juliet | W | Whisky | 0 | zero | j | juliet | w | whisky |
K | Kilo | X | X-ray | k | kilo | x | x-ray | ||
L | Lima | Y | Yankee | l | lima | y | yankee | ||
M | Mary | Z | Zulu | m | mary | z | zulu |
解题思路:
1、输出位移量需要加上输入内容和空格,所以这里是输出单词长度+2;
2、需要使用到的指令:
slt rd,rs,rt # 有符号的比较,if(rs<rt) rd=1 else rd=0
sgt rd,rs,rt # 有符号的比较,if(rs>rt) rd=1 else rd=0
sub rd,rs,rt # 有符号相减,rd=rs-rt
add rd,rs,rt # 与, rd=rs&rt
# 分支指令
beq rs,rt,imm # 相等则分支
bne rs,rt,imm # 不相等分支
beq reg1,reg2,L1
# if (value in reg1) == (value in reg2) goto L1
源码如下:
.data
ca_char: .asciiz
"Alpha ","Bravo ","China ","Delta ","Echo ","Foxtrot ",
"Golf ","Hotel ","India ","Juliet ","Kilo ","Lima ",
"Mary ","November ","Oscar ","Paper ","Quebec ","Research ",
"Sierra ","Tango ","Uniform ","Victor ","Whisky ","X-ray ",
"Yankee ","Zulu "
cc_offset: .word # offset = char_lenth + 2
0,7,14,21,28,34,43,49,56,63,71,
77,83,89,99,106,113,121,131,
139,146,155,163,171,178,186
lo_char: .asciiz
"alpha ","bravo ","china ","delta ","echo ","foxtrot ",
"golf ","hotel ","india ","juliet ","kilo ","lima ",
"mary ","november ","oscar ","paper ","quebec ","research ",
"sierra ","tango ","uniform ","victor ","whisky ","x-ray ",
"yankee ","zulu "
lc_offset: .word
0,7,14,21,28,34,43,49,56,63,71,
77,83,89,99,106,113,121,131,
139,146,155,163,171,178,186
number: .asciiz
"zero ", "First ", "Second ", "Third ", "Fourth ",
"Fifth ", "Sixth ", "Seventh ","Eighth ","Ninth "
n_offset: .word
0,6,13,21,28,36,43,50,59,67
.text
.globl main
main: li $v0, 12 # read character
syscall
sub $t1, $v0, 63 # ascii 63 = '?'
beqz $t1, exit
sub $t1, $v0, 48 # '0'
slt $s0, $t1, $0 # if t1 < 0 then s0 = 1
bnez $s0, others
# is number?
sub $t2, $t1, 10 # number
slt $s1, $t2, $0 # if t2 < 0 then s1 = 1
bnez $s1, getnum
# is capital?
sub $t2, $v0, 91 # 90 = 'Z'
slt $s3, $t2, $0 # if v0 <= 'Z' then s3 = 1
sub $t3, $v0, 64
sgt $s4, $t3, $0 # if v0 >= 'A' then s4 = 1
and $s0, $s3, $s4 # if s3 == 1 && s4 == 1
bnez $s0, getca_char
# is lower case?
sub $t2, $v0, 123 # 122 = 'z'
slt $s3, $t2, $0 # if v0 <= 'z' then s3 = 1
sub $t3, $v0, 96
sgt $s4, $t3, $0 # if v0 >= 'a' then s4 = 1
and $s0, $s3, $s4
bnez $s0, getlo_char
j others
getnum: add $t2, $t2, 10
sll $t2, $t2, 2
la $s0, n_offset
add $s0, $s0, $t2
lw $s1, ($s0)
la $a0, number
add $a0, $a0, $s1
li $v0, 4
syscall
j main
# upper case char
getca_char: sub $t3, $t3, 1
sll $t3, $t3, 2
la $s0, cc_offset
add $s0, $s0, $t3
lw $s1, ($s0)
la $a0, ca_char
add $a0, $s1, $a0
li $v0, 4
syscall
j main
# lower case char
getlo_char: sub $t3, $t3, 1
sll $t3, $t3, 2
la $s0, lc_offset
add $s0, $s0, $t3
lw $s1, ($s0)
la $a0, lo_char
add $a0, $s1, $a0
li $v0, 4
syscall
j main
others: and $a0, $0, $0
add $a0, $a0, 42 # '*'
li $v0, 11 # print character
syscall
j main
exit: li $v0, 10 # exit
syscall