ip地址转long

1.ip地址转long
def ip2Long(ip: String): Long = {
    val fragments: Array[String] = ip.split("[.]")
    var ipNum = 0L
    for (i <- 0 until fragments.length) {
      println(fragments(i))
      ipNum = fragments(i).toLong | (ipNum << 8L) // 1.|起到的作用实际为加            2.<<8l为乘以256            3.  第一个ipnum为125 第二个ipnum为0,而不是125|125<<8L
      println(ipNum)
    }
    println(ipNum)
    ipNum

125
125
213
32213
100
8246628
123
2111136891
2111136891
117
117
101
30053
215
7693783
133
1969608581
1969608581

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转载自blog.csdn.net/weixin_42923199/article/details/85092528