在Thread的构造函数中,可以显式地指定现成的Group,也就是ThreadGroup。
接下来我们看一下Thread的init方法源码:
private void init(ThreadGroup g, Runnable target, String name,
long stackSize, AccessControlContext acc,
boolean inheritThreadLocals) {
if (name == null) {
throw new NullPointerException("name cannot be null");
}
this.name = name;
Thread parent = currentThread();
SecurityManager security = System.getSecurityManager();
if (g == null) { //如果参数没有传入group
/* Determine if it's an applet or not */
/* If there is a security manager, ask the security manager
what to do. */
if (security != null) {
g = security.getThreadGroup();
}
/* If the security doesn't have a strong opinion of the matter
use the parent thread group. */
if (g == null) {
g = parent.getThreadGroup();
}
}
/* checkAccess regardless of whether or not threadgroup is
explicitly passed in. */
g.checkAccess();
/*
* Do we have the required permissions?
*/
if (security != null) {
if (isCCLOverridden(getClass())) {
security.checkPermission(SUBCLASS_IMPLEMENTATION_PERMISSION);
}
}
g.addUnstarted();
this.group = g;
this.daemon = parent.isDaemon();
this.priority = parent.getPriority();
if (security == null || isCCLOverridden(parent.getClass()))
this.contextClassLoader = parent.getContextClassLoader();
else
this.contextClassLoader = parent.contextClassLoader;
this.inheritedAccessControlContext =
acc != null ? acc : AccessController.getContext();
this.target = target;
setPriority(priority);
if (inheritThreadLocals && parent.inheritableThreadLocals != null)
this.inheritableThreadLocals =
ThreadLocal.createInheritedMap(parent.inheritableThreadLocals);
/* Stash the specified stack size in case the VM cares */
this.stackSize = stackSize;
/* Set thread ID */
tid = nextThreadID();
}
if (g == null) { //如果参数没有传入group
通过对源码进行分析,我们可以看出,如果在构造Thread的时候没有显示地指定一个ThreadGroup,那么子线程将会被加入父线程所在的线程组,下面我们来写一个简单的代码测试:
package lambda;
public class ThreadConstruction {
public static void main(String[] args) {
Thread t1 = new Thread("t1");
ThreadGroup g = new ThreadGroup("testGroup");
Thread t2 = new Thread(g,"t2");
ThreadGroup mainThreadGroup = Thread.currentThread().getThreadGroup();
System.out.println("Main thread belong the same group:"+mainThreadGroup.getName());
System.out.println("t1 and main belong the same group:"+(mainThreadGroup == t1.getThreadGroup()));
System.out.println("t2 thread group not belong main group:"+(mainThreadGroup == t2.getThreadGroup()));
System.out.println("t2 thread group not belong main testgroup:"+(g == t2.getThreadGroup()));
}
}
测试结果
Main thread belong the same group:main
t1 and main belong the same group:true
t2 thread group not belong main group:false
t2 thread group not belong main testgroup:true
听过对Thread源码的分析和我们自己的测试结果可以得出如下结论:
- main线程所在的ThreadGroup成为main
- 构造一个线程的时候如果没有显式地指定ThreadGroup,那么它将会和父线程同属于一个ThreadGroup。
在默认设置中,当然除了子线程和府县丞同属于一个group之外,它还会和父线程拥有相同的优先级。