pathon n级台阶问题

问题描述

一个人爬楼梯,每次只能爬1个或两个台阶,假设有n个台阶,那么这个人有多少种不同的爬楼梯方法

程序如下:

import time


def easy_step(num):
    if num > 2:
        out_num = easy_step(num-1) + easy_step(num-2)
    else:
        out_num = num
    return out_num


def comp_step(num):
    out_num = [0, 1, 2]
    for i in range(3, num+1):
        out_num.append(out_num[i-1]+out_num[i-2])
    return out_num[num]


def count_step(f):
    while True:
        s = input('请输入台阶数:')
        try:
            s = int(s)
            if s > 0:
                time1 = time.clock()
                r = f(s)
                time2 = time.clock()
                use_time = time2 - time1
                print('有%s种算法' % r)
                print('简单算法耗时:%f秒' % use_time)
                break
        except Exception:
            print('输入错误!')


count_step(easy_step)
count_step(comp_step)

运行结果:

请输入台阶数:15
有987种算法
简单算法耗时:0.000160秒
请输入台阶数:500
有225591516161936330872512695036072072046011324913758190588638866418474627738686883405015987052796968498626种算法
简单算法耗时:0.000111秒

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转载自blog.csdn.net/happyuu/article/details/83901779