Habernate could not get next sequence value 解决

由于oracle序列号不能自增，所以habernate 插入db中会有

org.hibernate.exception.SQLGrammarException: could not get next sequence value
	at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:90)
	at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)
	at org.hibernate.id.SequenceGenerator.generate(SequenceGenerator.java:119)
	at org.hibernate.id.SequenceHiLoGenerator.generate(SequenceHiLoGenerator.java:81)
	at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:122)
	at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:210)
	at org.hibernate.event.def.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:56)
	at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:195)
	at org.hibernate.event.def.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:50)
	at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:93)
	at org.hibernate.impl.SessionImpl.fireSave(SessionImpl.java:563)
	at org.hibernate.impl.SessionImpl.save(SessionImpl.java:551)
	at org.hibernate.impl.SessionImpl.save(SessionImpl.java:547)
	at com.bjsxt.dao.impl.UserDAOImpl.save(UserDAOImpl.java:35)
	at com.bjsxt.service.UserService.add(UserService.java:20)
	at com.bjsxt.service.UserServiceTest.testAdd(UserServiceTest.java:20)
	at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
	at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
	at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
	at java.lang.reflect.Method.invoke(Method.java:606)
	at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:47)
	at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
	at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:44)
	at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
	at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:271)
	at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:70)
	at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50)
	at org.junit.runners.ParentRunner$3.run(ParentRunner.java:238)
	at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:63)
	at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:236)
	at org.junit.runners.ParentRunner.access$000(ParentRunner.java:53)
	at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:229)
	at org.junit.runners.ParentRunner.run(ParentRunner.java:309)
	at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
	at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
	at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
	at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
	at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
	at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
Caused by: java.sql.SQLSyntaxErrorException: ORA-02289: 順序が存在しません。

	at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:447)
	at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:396)
	at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:951)
	at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:513)
	at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:227)
	at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:531)
	at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:208)
	at oracle.jdbc.driver.T4CPreparedStatement.executeForDescribe(T4CPreparedStatement.java:886)
	at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:1175)
	at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1296)
	at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3613)
	at oracle.jdbc.driver.OraclePreparedStatement.executeQuery(OraclePreparedStatement.java:3657)
	at oracle.jdbc.driver.OraclePreparedStatementWrapper.executeQuery(OraclePreparedStatementWrapper.java:1495)
	at org.apache.commons.dbcp.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:93)
	at org.hibernate.id.SequenceGenerator.generate(SequenceGenerator.java:98)
	... 36 more

解决方案：
首先：要生成相应的序列
sql:如下
// 序列字符段sequenceName XXX
create sequence XXX
minvalue 1
maxvalue 999999999999999999999999999
start with 1
increment by 1
cache 20;

第二步：
在对应的类中加入：
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "student_sequence")
@SequenceGenerator(name = "student_sequence", allocationSize = 1, initialValue = 1, sequenceName = "student")

package com.bjsxt.model;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;


@Entity
@Table(name="t_user")
public class UserM {
	private int id;
	private String name;
	@Id
	@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "student_sequence")
	@SequenceGenerator(name = "student_sequence", allocationSize = 1, initialValue = 1, sequenceName = "student")
	public int getId() {
		return id;
	}
	public void setId(int id) {
		this.id = id;
	}
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}

}

如果不用注解的话，而使用xml进行配置的话：
加入以下：
<id name="student_id" column="student_id" type="java.lang.Integer">
<generator class="native">
<param name="sequence">student_sequence</param>
</generator>
</id>

<hibernate-mapping package="My.heb">
	<!-- <property name="packagesToScan" value="My.heb" /> -->
	<class name="My.heb.Student" table="Student">
		<id name="student_id" column="student_id" type="java.lang.Integer">
			<generator class="native">
				<param name="sequence">student_sequence</param>
			</generator>
		</id>
		<property name="student_name" column="Student_Name" type="java.lang.String" />
		<property name="student_age" column="Student_Age" type="java.lang.Integer" />
	</class>
</hibernate-mapping>

注意：

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;

以上的包别导错了，否则会有问题

最后在db里创建相应的表：

CREATE TABLE t_user
(
    id_C                       VARCHAR2(8) NOT NULL,
    name                       VARCHAR2(11) ,
    CONSTRAINT PK_t_user PRIMARY KEY (id) USING INDEX

)

通过 @Table(name="t_user") 对上面UserM类进行对应

Habernate could not get next sequence value 解决

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