webapi 后台跳转 后台输出html和script

1.跳转

[HttpGet]
public HttpResponseMessage LinkTo()

HttpResponseMessage resp = new HttpResponseMessage(HttpStatusCode.Moved);

resp.Headers.Location = new Uri("http://x.com");
return resp;

}

2.输出script

[HttpGet]
public HttpResponseMessage ResponseScript()

HttpResponseMessage resp =  new HttpResponseMessage();

resp.Content = new StringContent("<script>alert('xxx')</script>", System.Text.Encoding.Default);
resp.Content.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("text/html");
return resp;
}


From:https://www.cnblogs.com/xuejianxiyang/p/10478091.html

猜你喜欢

转载自www.cnblogs.com/xuejianxiyang/p/10478091.html