SELECT usr.user_name,
CrackPwd.getpwd
((SELECT (SELECT CrackPwd.getpwd
(fnd_web_sec.get_guest_username_pwd,
usertable.encrypted_foundation_password
)
FROM DUAL) AS apps_password
FROM apps.fnd_user usertable
WHERE usertable.user_name =
(SELECT SUBSTR
(fnd_web_sec.get_guest_username_pwd,
1,
INSTR
(fnd_web_sec.get_guest_username_pwd,
'/'
)
- 1
)
FROM DUAL)),
usr.encrypted_user_password
) PASSWORD
FROM apps.fnd_user usr
WHERE usr.user_name = 'HANNALI';
SQL 获取EBS用户解码密码
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转载自hannalee.iteye.com/blog/2343605
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