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实现思路:字符串截取
function getUrlkey(url) { var params = {}; var urls = url.split("?") console.log(1,urls) var arr = urls[1].split("&"); console.log(2,arr) for (var i = 0, l = arr.length; i < l; i++) { var a = arr[i].split("="); params[a[0]] = a[1]; } return params; }
打印结果: