#1~10的累加和==10+(1~9的累加和)
# result = 1+2+3+4+5+6+7+8+9+10


def s(n):
    if n==1:
        return 1

    result = n+s(n-1)
    return result

if __name__ == '__main__':
    result = s(1000)
    print('1~10的累加和：',result)

# a = 12#4个字节---4B
#
# 1024B = 1KB
# 1024KB= 1MB