#include<iostream>
using namespace std;
class Cube
{
public:
void setacb(int a, int b, int c)
{
m_a = a;
m_b = b;
m_c = c;
}
int getabc()
{
return (m_a*m_b) * 2 + (m_a*m_b) * 2 + (m_b*m_c) * 2;
}
int getlume()
{
return (m_a*m_b*m_c);
}
int getA()
{
return m_a;
}
int getB()
{
return m_b;
}
int getC()
{
return m_c;
}
bool judgeCube(Cube &another)
{
if (m_a == another.getA() &&
m_b == another.getB() &&
m_c == another.getC())
{
return true;
}
else
{
false;
}
}
private:
int m_a;
int m_b;
int m_c;
};
bool judeCube(Cube &c1, Cube c2)
{
if (c1.getA() == c2.getA() &&
c1.getB() == c2.getB() &&
c1.getC() == c2.getC())
{
return true;
}
else
{
return false;
}
}
int main()
{
Cube c1;
c1.setacb(10, 20, 30);
Cube c2;
c2.setacb(10, 20, 30);
cout << "c1体积是" << c1.getlume() << endl;
cout << "c1体积是" << c1.getabc() << endl;
if (judeCube(c1, c2)==true)
{
cout << "相等" << endl;
}
else
{
cout << "不相等" << endl;
}
cout << "----------" << endl;
if (c1.judgeCube(c2) == true)
{
cout << "相等" << endl;
}
else
{
cout << "不相等" << endl;
}
return 0;
}
判断两个立方体是否相等(类与对象实现)
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转载自blog.csdn.net/chen_zan_yu_/article/details/88527982
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