from itertools import product
a = (1, 2, 3)
b = ('A', 'B', 'C')
c = ('d', 'e', 'f')
pros = product(a, b, c)
count = 1
for elem in pros:
    print(f'{count:02}', "---", elem)
    count+=1

output:
01 --- (1, 'A', 'd')
02 --- (1, 'A', 'e')
03 --- (1, 'A', 'f')
04 --- (1, 'B', 'd')
05 --- (1, 'B', 'e')
06 --- (1, 'B', 'f')
07 --- (1, 'C', 'd')
08 --- (1, 'C', 'e')
09 --- (1, 'C', 'f')
10 --- (2, 'A', 'd')
11 --- (2, 'A', 'e')
12 --- (2, 'A', 'f')
13 --- (2, 'B', 'd')
14 --- (2, 'B', 'e')
15 --- (2, 'B', 'f')
16 --- (2, 'C', 'd')
17 --- (2, 'C', 'e')
18 --- (2, 'C', 'f')
19 --- (3, 'A', 'd')
20 --- (3, 'A', 'e')
21 --- (3, 'A', 'f')
22 --- (3, 'B', 'd')
23 --- (3, 'B', 'e')
24 --- (3, 'B', 'f')
25 --- (3, 'C', 'd')
26 --- (3, 'C', 'e')
27 --- (3, 'C', 'f')

a = (0, 1)
b = (0, 1)
c = (0, 1)
pros = product(a, b, c)
count = 1
for elem in pros:
    print(f'{count:02}', "---", elem)
    count+=1

output:
01 --- (0, 0, 0)
02 --- (0, 0, 1)
03 --- (0, 1, 0)
04 --- (0, 1, 1)
05 --- (1, 0, 0)
06 --- (1, 0, 1)
07 --- (1, 1, 0)
08 --- (1, 1, 1)

from itertools import chain
[e for e in chain([2, 3], {3, 4}, (3,4))]

output:
[2, 3, 3, 4, 3, 4]