info_list=[{‘name’:‘zhang’,‘age’:‘19’},
{‘name’:‘xu’,‘age’:‘10’},
{‘name’:‘mei’,‘age’:‘17’}]
info_list.sort(key=lambda x:x[‘age’])
print(info_list)
#输出[{‘name’: ‘xu’, ‘age’: ‘10’}, {‘name’: ‘mei’, ‘age’: ‘17’}, {‘name’: ‘zhang’, ‘age’: ‘19’}]
#寻找三个变量中的最大值
print((lambda a,b,c:c if c>(a if a>b else b) else (a if a>b else b))(1,22,33))
#输出33
#1、表达式大多是一行代码,没有复杂操作
#2、默认有返回值