Resource指出类的别名,spring在xml中查找id或name与之对应
xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<bean name = "userService" class = "com.hxzy.springbase.service.impl.UserServiceImpl" scope = "singleton" autowire = "byType"></bean>
<bean id = "userDao" class = "com.hxzy.springbase.dao.impl.UserDaoImpl"></bean>
</beans>
测试
public class Test1 {
@Test
public void test1() {
System.out.println("1");
BeanFactory bean = new ClassPathXmlApplicationContext("./spring-bean.xml");
System.out.println("2");
UserServiceImpl userServiceImpl = (UserServiceImpl) bean.getBean("userService");
System.out.println("3");
userServiceImpl.addUser();
}
}
service
public class UserServiceImpl {
private UserDao userDao;
public void addUser() {
userDao.addUser();
}
@Autowired
public void setUserDao(@Qualifier("userDao")UserDao userDao) {
System.out.println("进去了set");
this.userDao = userDao;
}
public UserDao getUserDao() {
return userDao;
}
}
无注解接口注入
public class Test1 {
@Test
@Resource(name = "userService")
public void test1() {
System.out.println("1");
BeanFactory bean = new ClassPathXmlApplicationContext("./spring-bean.xml");
System.out.println("2");
UserServiceImpl userServiceImpl = (UserServiceImpl) bean.getBean("userService");
System.out.println("3");
userServiceImpl.addUser();
}
}
xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package = "com.hxzy.springbase" scoped-proxy = "interfaces"></context:component-scan>
<bean name = "userDao" class = "com.hxzy.springbase.dao.impl.UserDaoImpl"></bean> -->
<bean name = "userService" class = "com.hxzy.springbase.service.impl.UserServiceImpl" scope = "singleton" autowire = "byType"></bean>
</beans>
service
public class UserServiceImpl {
private UserDao userDao;
public void addUser() {
userDao.addUser();
}
public void setUserDao(UserDao userDao) {
System.out.println("进去了set");
this.userDao = userDao;
}
public UserDao getUserDao() {
return userDao;
}
}
pom
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.hxzy</groupId>
<artifactId>springbase</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>jar</packaging>
<name>springbase</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
<!-- https://mvnrepository.com/artifact/junit/junit -->
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.0</version>
<scope>test</scope>
</dependency>
<!-- spring bean -->
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-beans</artifactId>
<version>4.0.0.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>4.0.0.RELEASE</version>
</dependency>
</dependencies>
</project>