版权声明：本文为博主原创文章，未经博主允许不得转载。 https://blog.csdn.net/a973893384/article/details/7927642
#include "stdafx.h"
struct person
{
char name[21];
int count;
}L[3]={"Li",0,"Zhang",0,"Wang",0};
int main(int argc, char* argv[])
{
int i=0,t,e;
int k;
puts("1:Li 2:Zhang 3:Wang");
while(i<20)
{
scanf("%d",&k);
switch (k)
{
case 1:L[0].count++;
case 2:L[1].count++;
case 3:L[2].count++;
}
i++;
}
t=L[0].count;
for(int j=0;j<3;j++)
if(t<L[j].count)
{
t=L[j].count;
e=j;
}
printf("%s is zhouzhang\n",L[e].name);
return 0;
}