list有序集合答案

private static List<Integer> sSorted = new LinkedList<>();
public static void addElement(int e) {
    int i;
    for (i = 0; i < sSorted.size(); ++i) {
        if (e <= sSorted.get(i)) {
            break;
        }
    }
    sSorted.add(i, e);
}

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转载自blog.csdn.net/qq_41426326/article/details/89207681