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sql:
SELECT @s :=@s + 1 as 'index', DATE(DATE_SUB(CURRENT_DATE, INTERVAL @s DAY)) AS 'date' FROM mysql.help_topic,(SELECT @s := -1) temp WHERE @s < 7 ORDER BY 'date' ;
结果:
index |
date |
0 |
2019-03-06 |
1 |
2019-03-05 |
2
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|
2019-03-04 |
3 |
2019-03-03 |
4 |
2019-03-02 |
5 |
2019-03-01 |
6 |
2019-02-28 |
7 |
2019-02-27 |