Complete the function scramble(str1, str2) that returns true if a portion of str1 characters can be rearranged to match str2, otherwise returns false.

Notes:

• Only lower case letters will be used (a-z). No punctuation or digits will be included.
• Performance needs to be considered

Input strings s1 and s2 are null terminated.

Examples

scramble('rkqodlw', 'world') ==> True
scramble('cedewaraaossoqqyt', 'codewars') ==> True
scramble('katas', 'steak') ==> False

代码：

public class Scramblies {
    public static boolean scramble(String str1, String str2) {
        for(int i=0;i<str2.length();i++){
            String str=String.valueOf(str2.charAt(i));
            if(!str1.contains(str)){
                return false;
            }
            str1=str1.replaceFirst(str,"");
        }
        return true;
    }

    public static boolean scramble2(String str1, String str2) {
        if (str2.length() > str1.length()) return false;
        for (String s: str2.split("")) {
            if (!str1.contains(s))  return false;
            str1 = str1.replaceFirst(s,"");
        }
        return true;
    }

    public static void main(String[] args) {
        System.out.println(scramble("scriptjavx","javascript"));
        System.out.println(scramble2("scriptjavx","javascript"));
    }
}