NBUT 1228 Bored Three-God

题意:大数加法;

坑点:输入有前导0,输出也有前导0.。。;

#include<stdio.h>
#include<iostream>
#include<algorithm>
#include<string.h>
#include<stdlib.h>
#include<time.h>
#include<string>
#include<math.h>
#include<map>
#include<queue>
#include<stack>
const int inf=0x3f3f3f3f;
typedef long long ll;
using namespace std;
int x[10005],y[10005],z[10005];
char a[10005],b[10005];
int main()
{
    while(~scanf("%s%s",a,b))
    {
        memset(z,0,sizeof(z));
        memset(x,0,sizeof(x));
        memset(y,0,sizeof(y));
        int aa=strlen(a);
        int bb=strlen(b);
        int p=0;
        for(int i=aa-1; i>=0; i--)x[p++]=a[i]-'0';
        p=0;
        for(int i=bb-1; i>=0; i--)y[p++]=b[i]-'0';
        int d=0;
        p=max(aa,bb);
        for(int i=0;i<=p; i++)
        {
            int s=x[i]+y[i]+d;
            z[i]=s%10;
            d=s/10;
        }
        if(z[p])printf("%d",z[p]);
        for(int i=p-1; i>=0; i--)
            printf("%d",z[i]);
        printf("\n");
    }
}

猜你喜欢

转载自blog.csdn.net/qq_41984014/article/details/88880248