字符串转数字(num=num*10+str[i]-‘0’)
num=atoi(str)
#include<bits/stdc++.h>
using namespace std;
int main()
{
int num;
char str[233];
cin >> str;
num=atoi(str);
cout << num << endl;
return 0;
}
数字转字符串
while(num)
{
str[t++]=num%10+‘0’;
num/=10;
}
ito
a(num,str,进制)
#include<bits/stdc++.h>
using namespace std;
int main()
{
int num;
char str[233];
cin >> num;
itoa(num,str,10);
cout << str <<endl;
return 0;
}