Poj1094

题目大意:将字母按照所给的序列从小到大输出。

算法思路:首先判断该图是否存在环,如果不存在,看能否进行有序输出,如果有序则后面的处理步骤都可以跳过,否则输出题目所给的话。

#include<iostream>
#include<string>
using namespace std;
int n,m,indegree[30],map[30][30];
char ans[30];
int topusort()
{
	int temp[30],sym=0,i,j,m,flag,res=1;
	for(i=0;i<n;i++)
	{
		temp[i]=indegree[i];
	}
	for(i=0;i<n;i++)
	{
		m=0;
		for(j=0;j<n;j++)
		{
			if(temp[j]==0)
			{
				m++;
				flag=j;
			}
		}
		if(m==0)//说明有环
			return 0;
		if(m>1)
			res=-1;
		ans[sym++]=flag+'A';
		temp[flag]=-1;
		for(j=0;j<n;j++)
		{
			if(map[flag][j]>0)
				temp[j]--;
		}

	}
	return res;

}
int main()
{
	int i,j,sign;
	string s;
	while(scanf("%d%d",&n,&m)&&(n!=0||m!=0))
	{
		sign=0;
		memset(ans,0,sizeof(ans));
		memset(map,0,sizeof(map));
		memset(indegree,0,sizeof(indegree));
		for(i=1;i<=m;i++)
		{
			cin>>s;
			if(sign)
				continue;
			int x=s[0]-'A';
			int y=s[2]-'A';
			map[x][y]=1;
			indegree[y]++;
			int ss=topusort();
			if(ss==0)//有环
			{
				cout<<"Inconsistency found after "<<i<<" relations."<<endl;
				sign=1;
			}
			if(ss==1)//有序
			{
				cout<<"Sorted sequence determined after "<<i<<" relations: ";
				for(j=0;j<n;j++)
				{
					cout<<ans[j];
				}
				cout<<"."<<endl;
				sign=1;
			}
		}
		if(!sign)
			cout<<"Sorted sequence cannot be determined."<<endl;
	}

}

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转载自huyifan951124.iteye.com/blog/2316015