Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
1 22 23 34 3
Sample Output
NOYESYESNO
//水题，关键在小数点
#include <stdio.h>#include <string.h>#include <iostream>using namespace std; char a[100000],b[100000];void change(char s[]){ int i,len; len = strlen(s); if(strstr(s,".")) { for(i = len-1; s[i] == '0'; i--) { s[i] = '\0'; len--; } } if(s[len-1] == '.') s[len-1] = '\0';}int main(){ while(scanf("%s%s",a,b)!=EOF) { change(a); change(b); if(strcmp(a,b)) printf("NO\n"); else printf("YES\n"); } return 0;}