将表c中的journal_full_name用表s中的journal_full_name填充,根据相同的id
方法一
update c
set c.journal_full_name=s.journal_full_name
from reference_new_copy AS c,reference_new_some AS s
where c.id=s.id;
此方法对版本有要求,未试验成功
方法二
将两张表以内连接的方式进行查询更新
UPDATE reference_new_copy c
INNER JOIN reference_new_some s
ON c.id=s.id
SET c.journal_full_name=s.journal_full_name
该方法测试OK