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1 import time 2 3 4 # 时间戳:从1970年后经过的秒数 5 print(time.time()) 6 #1558538588.7168798 7 8 # 时间戳 --> 时间元组 9 #年 月 日 时 分 秒 星期(周一0 周二1 ... 周日6) 一年的第几天 夏令时 10 tuple_time = time.localtime(1558538588.7168798) 11 print(tuple_time) 12 #time.struct_time(tm_year=2019, tm_mon=5, tm_mday=22, tm_hour=23, tm_min=23, tm_sec=8, tm_wday=2, tm_yday=142, tm_isdst=0) 13 14 # 时间元组 --> str 15 # 年/月/日 小时:分钟:秒 16 print(time.strftime("%y/%m/%d %H:%M:%S",tuple_time)) 17 #19/05/22 23:23:08 18 print(time.strftime("%Y/%m/%d %H:%M:%S",tuple_time)) 19 #2019/05/22 23:23:08 (y与Y的区别) 20 21 # str --> 时间元组 22 print(time.strptime("2019-05-21","%Y-%m-%d")) 23 #time.struct_time(tm_year=2019, tm_mon=5, tm_mday=21, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=1, tm_yday=141, tm_isdst=-1) 24 25 # 时间元组 --> 时间戳 26 print(time.mktime(tuple_time)) 27 #1558538588.0
练习1:根据年月日,返回星期几
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1 import time 2 3 def get_week(year,month,day): 4 str_time=time.strptime("%d-%d-%d"%(year,month,day),"%Y-%m-%d") 5 dict_week={ 6 0:"星期一", 7 1:"星期二", 8 2:"星期三", 9 3:"星期四", 10 4:"星期五", 11 5:"星期六", 12 6:"星期日" 13 } 14 return dict_week[str_time[6]] 15 16 print(get_week(2019,5,22))
练习2:根据年月日,算出活了多少天
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1 import time 2 3 4 # 思路:先算当前时间戳,再算出生时间戳 两者相减 便是活的天数 5 def life_days(year, month, day): 6 days = time.time() - time.mktime(time.strptime("%d-%d-%d" % (year, month, day), "%Y-%m-%d")) 7 return days / 60 / 60 // 24 8 9 10 print(life_days(2019, 5, 2))