randn
创建服从标准正态分布的数组
import numpy as np
np.random.randn(10) #标准正态分布,个数为10
>>>array([-1.33451923, 0.91043749, 0.71773473, 0.56788441, 1.02108645,
1.26399891, 1.10158509, 0.52190488, 0.03587553, -0.31124879])
randint
#返回10以内的随机的,int型数据
np.random.randint(10)
>>>1
#创建一个数组,2x3,int型
np.random.randint(10, size=(2,3))
array([[3, 5, 4],
[7, 5, 0]])
#创建一个一维的数组。它是随机的,int型,长度为20
np.random.randint(10, size=20)
>>>array([3, 6, 9, 8, 5, 5, 8, 6, 0, 9, 3, 0, 2, 7, 4, 2, 4, 9, 4, 8])
reshape
#reshape数组为4x5
np.random.randint(10, size=20).reshape(4,5)
>>>array([[6, 7, 8, 4, 5],
[2, 0, 5, 6, 7],
[9, 0, 3, 0, 5],
[3, 2, 3, 5, 3]])