#include <stdio.h>
int main(){
int i = 2, j = 3;
int count = 0;
int result;
int arr[20];
for(int k = 1; k <= 20; k++){
if(k == 1){
arr[k] = 2;
count++;
printf("%d ", arr[k]);
}else if(k == 2){
arr[k] = 3;
count++;
printf("%d ", arr[k]);
}else{
arr[k] = i + j;
result = i + j;
i = j;
j = result;
count++;
printf("%d ", arr[k]);
}
}
printf("count = %d\n", count);
return 0;
}
创建一个有20个值的数组,前两项的值为2,3,之后的每一个值等于前两项的和.
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转载自blog.csdn.net/Huwence/article/details/94402049
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